Current Electricity

Question: There is a current of 40 ampere in a wire of $10^{-6}m^2$ area of cross-section. If the number of free electron per $m^3$ is $10^{29}$, then the drift velocity will be

1) $1.25 \times 10^3 m/s$

2) $2.50 \times 10^{-3} m/s$

3) $25.0 \times 10^{-3} m/s$

4) $250 \times 10^{-3} m/s

Solution:

Explanation: No Explanation

Electric Conduction Ohm's Law Resistance

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