Categories > Electrostatics > electric-field-potential > Two parallel plates separated by a distance of $5mm$ are kept at a potential difference of $50\,V.$A particle of mass ${10^{ - 15}}kg$ and charge ${10^{ - 11}}C$ enters in it with a velocity ${10^7}m/s$. The acceleration of the particle will be

Electrostatics

Question: Two parallel plates separated by a distance of $5mm$ are kept at a potential difference of $50\,V.$A particle of mass ${10^{ - 15}}kg$ and charge ${10^{ - 11}}C$ enters in it with a velocity ${10^7}m/s$. The acceleration of the particle will be


1) ${10^8}m/{s^2}$
2) $5 \times {10^5}m/{s^2}$
3) ${10^5}m/{s^2}$
4) $2 \times {10^3}m/{s^2}$
Solution: Explanation: Explanation
electric-field-potential

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