Electrostatics

Question: As shown in the figure, charges $+ q$ and $- q$ are placed at the vertices $B$and $C$of an isosceles triangle. The potential at the vertex A is

1) $\frac{1}{{4\pi {\varepsilon _0}}}.\frac{{2q}}{{\sqrt {{a^2} + {b^2}} }}$

2) Zero

3) $\frac{1}{{4\pi {\varepsilon _0}}}.\frac{q}{{\sqrt {{a^2} + {b^2}} }}$

4) $\frac{1}{{4\pi {\varepsilon _0}}}.\frac{{( - q)}}{{\sqrt {{a^2} + {b^2}} }}$

Solution:

Explanation: Explanation

electric-field-potential

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