Categories > Units and Measurements > Errors-in-Measurement > In an experiment, the following observation's were recorded : L = 2.820 m, M = 3.00 kg, l = 0.087 cm, Diameter D = 0.041 cm Taking g = 9.81 $m/{s^2}$using the formula , Y=$\frac{{4MgL}}{{\pi {D^2}l}}$, the maximum permissible error in Y is

Units and Measurements

Question: In an experiment, the following observation's were recorded : L = 2.820 m, M = 3.00 kg, l = 0.087 cm, Diameter D = 0.041 cm Taking g = 9.81 $m/{s^2}$using the formula , Y=$\frac{{4MgL}}{{\pi {D^2}l}}$, the maximum permissible error in Y is


1) 7.96%
2) 4.56%
3) 6.50%
4) 8.42%
Solution: Explanation: explanation
Errors-in-Measurement

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