Electrostatics

Question: If a charged spherical conductor of radius $10\,cm$ has potential $V$ at a point distant $5\,cm$ from its centre, then the potential at a point distant $15\,cm$ from the centre will be

1) $\frac{1}{3}V$

2) $\frac{2}{3}V$

3) $\frac{3}{2}V$

4) $3V$

Solution:

Explanation: Explanation

electric-field-potential

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