Electrostatics

Question: In Millikan's oil drop experiment an oil drop carrying a charge Q is held stationary by a potential difference $2400\,V$ between the plates. To keep a drop of half the radius stationary the potential difference had to be made $600\,V$. What is the charge on the second drop



1) $\frac{Q}{4}$
2) $\frac{Q}{2}$
3) $Q$
4) $\frac{{3Q}}{2}$
Solution: Explanation: Explanation
electric-field-potential

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