Categories > Electrostatics > electric-field-potential > Three particles, each having a charge of $10\,\mu C$are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is (Given $\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}N - {m^2}/{C^2}$)

Electrostatics

Question: Three particles, each having a charge of $10\,\mu C$are placed at the corners of an equilateral triangle of side $10\,cm$. The electrostatic potential energy of the system is (Given $\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {10^9}N - {m^2}/{C^2}$)


1) Zero
2) Infinite
3) $27\,J$
4) $100\,J$
Solution: Explanation: Explanation
electric-field-potential

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)

Previous Question Next Question

Related Questions