Motion in A Plane

Question: A stone is thrown at an angle $\theta $to the horizontal reaches a maximum height H. Then the time of flight of stone will be



1) $\sqrt {\frac{{2H}}{g}} $
2) $2\,\sqrt {\frac{{2H}}{g}}$
3) $\frac{{2\sqrt {2H\,\sin \theta } }}{g}$
4) $\frac{{\sqrt {2H\,\sin \theta } }}{g}$
Solution: Explanation: Explanation
oblique-projectile-motion

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