Categories > Motion in A Plane > oblique-projectile-motion > A stone projected with a velocity u at an angle $\theta$ with the horizontal reaches maximum height $H_1$. When it is projected with velocity u at an angle $\left( {\frac{\pi }{2} - \theta } \right)$ with the horizontal, it reaches maximum height $H_2$. The relation between the horizontal range R of the projectile, $H_1$ and $H_2$ is

Motion in A Plane

Question: A stone projected with a velocity u at an angle $\theta$ with the horizontal reaches maximum height $H_1$. When it is projected with velocity u at an angle $\left( {\frac{\pi }{2} - \theta } \right)$ with the horizontal, it reaches maximum height $H_2$. The relation between the horizontal range R of the projectile, $H_1$ and $H_2$ is


1) $R = 4\sqrt {{H_1}{H_2}} $
2) $R = 4({H_1} - {H_2})$
3) $R = 4({H_1} + {H_2})$
4) $R = \frac{{{H_1}^2}}{{{H_2}^2}}$
Solution: Explanation: Explanation
oblique-projectile-motion

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)

Previous Question Next Question

Related Questions