Motion in A Plane

Question: If the range of a gun which fires a shell with muzzle speed $V$ is $R$, then the angle of elevation of the gun is

1) ${\cos ^{ - 1}}\left( {\frac{{{V^2}}}{{Rg}}} \right)$

2) ${\cos ^{ - 1}}\left( {\frac{{gR}}{{{V^2}}}} \right)$

3) $\frac{1}{2}\left( {\frac{{{V^2}}}{{Rg}}} \right)$

4) $\frac{1}{2}{\sin ^{ - 1}}\left( {\frac{{gR}}{{{V^2}}}} \right)$

Solution:

Explanation: Explanation

oblique-projectile-motion

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