Motion in A Plane

Question: The angle of projection at which the horizontal range and maximum height of projectile are equal is

1) ${45^o}$

2) $\theta = {\tan ^{ - 1}}(0.25)$

3) $\theta = {\tan ^{ - 1}}4$or $(\theta = 76^\circ )$

4) ${60^o}$

Solution:

Explanation: Explanation

oblique-projectile-motion

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