Motion in A Plane

Question: A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground will be \[(g = 10\,\,m/{s^2})\]



1) \[{\tan ^{ - 1}}\left( {\frac{1}{5}} \right)\]
2) \[\tan \,\left( {\frac{1}{5}} \right)\]
3) \[{\tan ^{ - 1}}(1)\]
4) \[{\tan ^{ - 1}}(5)\]
Solution: Explanation: Explanation
horizontal-projectile-motion

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