Units and Measurements

Question: The period of oscillation of a simple pendulum is given by $T = 2\pi \sqrt {\frac{l}{g}} $where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1 s. The percentage error in g is



1) 0.10%
2) 1%
3) 0.20%
4) 0.80%
Solution: Explanation: explanation
Errors-in-Measurement

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