Electrostatics

Question: Two point charges $3 \times 10^{–6}C$ and $8 \times 10^{–6}$ C repel each other by a force of $6 \times 10^{–3} N. If each of them is given an additional charge $– 6 \times 10^6$ C, the force between them will be

1) $2.4 \times 10^{–3}$ N (attractive)

2) $2.4 \times 10^{–9}$ N (attractive)

3) $1.5 \times 10^{–3}$ N (repulsive)

4) $1.5 \times 10^{–3}$ N (attractive)

Solution:

Explanation: No Explanation

Coulomb's Law

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