Categories > Gravitation > Gravitation Potential > The radius of a planet is $\frac{1}{4}$ of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many times will the escape velocity at the planet’s surface be as compared to its value on earth’s surface

Gravitation

Question: The radius of a planet is $\frac{1}{4}$ of earth’s radius and its acceleration due to gravity is double that of earth’s acceleration due to gravity. How many times will the escape velocity at the planet’s surface be as compared to its value on earth’s surface


1) $\frac{1}{{\sqrt 2 }}$
2) $\sqrt 2$
3) $2\sqrt 2$
4) 2
Solution: Explanation: No Explanation
Gravitation Potential Gravitational Potential Energy and Escape Velocity

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