Gravitation

Question: The gravitational field due to a mass distribution is $E = K/{x^3}$ in the x-direction. (K is a constant). Taking the gravitational potential to be zero at infinity, its value at a distance x is

1) K/x

2) K/2x

3) $K/{x^2}$

4) $K/2{x^2}$

Solution:

Explanation: No Explanation

Gravitation Potential Gravitational Potential Energy and Escape Velocity

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