Categories > Gravitation > Acceleration Due to Gravity > Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth. If the ratio of densities of earth $({\rho _e})$ and moon $({\rho _m})$ is $\left( {\frac{{{\rho _e}}}{{{\rho _m}}}} \right) = \frac{5}{3}$ then radius of moon Rm in terms of Re will be

Gravitation

Question: Acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth. If the ratio of densities of earth $({\rho _e})$ and moon $({\rho _m})$ is $\left( {\frac{{{\rho _e}}}{{{\rho _m}}}} \right) = \frac{5}{3}$ then radius of moon Rm in terms of Re will be


1) $\frac{5}{{18}}{R_e}$
2) $\frac{1}{6}{R_e}$
3) $\frac{3}{{18}}{R_e}$
4) $\frac{1}{{2\sqrt 3 }}{R_e}$
Solution: Explanation: No Explanation
Acceleration Due to Gravity

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