R is the radius of the earth and $\omega$ is its angular velocity and ${g_p}$ is the value of g at the poles. The effective value of g at the latitude $\lambda = 60^\circ$ will be equal to

Question

Accepted Answer

${g_p} - \frac{1}{4}R{\omega ^2}$

Answer

${g_p} - \frac{3}{4}R{\omega ^2}$

Answer

${g_p} - R{\omega ^2}$

Answer

${g_p} + \frac{1}{4}R{\omega ^2}$

Gravitation

Question: R is the radius of the earth and $\omega$ is its angular velocity and ${g_p}$ is the value of g at the poles. The effective value of g at the latitude $\lambda = 60^\circ$ will be equal to

Gravitation

Question: R is the radius of the earth and $\omega$ is its angular velocity and ${g_p}$ is the value of g at the poles. The effective value of g at the latitude $\lambda = 60^\circ$ will be equal to

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