Work, Energy and Power

Question: A ball of mass m falls vertically to the ground from a height h1 and rebound to a height ${h_2}$. The change in momentum of the ball on striking the ground is



1) $mg({h_1} - {h_2})$
2) $m(\sqrt {2g{h_1}} + \sqrt {2g{h_2}} )$
3) $m\sqrt {2g({h_1} + {h_2})}$
4) $m\sqrt {2g} ({h_1} + {h_2})$
Solution: Explanation: No Explanation
WEP Elastic and Inelastic collision

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