Work, Energy and Power

Question: Two identical cylindrical vessels with their bases at same level each contains a liquid of density ?. The height of the liquid in one vessel is ${h_1}$ and that in the other vessel is ${h_2}$. The area of either base is A. The work done by gravity in equalizing the levels when the two vessels are connected, is



1) $({h_1} - {h_2})g\rho$
2) $({h_1} - {h_2})gA\rho$
3) $\frac{1}{2}{({h_1} - {h_2})^2}gA\rho$
4) $\frac{1}{4}{({h_1} - {h_2})^2}gA\rho$
Solution: Explanation: No Explanation
WEP Conservation of Energy and Momentum

Rate this question:

Average rating: (0 votes)

Previous Question Next Question