Work, Energy and Power

Question: The force constant of a wire is k and that of another wire is $2k.$ When both the wires are stretched through same distance, then the work done



1) ${W_2} = 2W_1^2$
2) ${W_2} = 2{W_1}$
3) ${W_2} = {W_1}$
4) ${W_2} = 0.5{W_1}$
Solution: Explanation: No Explanation
WEP Work Done by Variable Force

Rate this question:

Average rating: (0 votes)

Previous Question Next Question