Categories > Work, Energy and Power > WEP > A force acts on a 30 gm particle in such a way that the position of the particle as a function of time is given by $x = 3t - 4{t^2} + {t^3}$, where x is in metres and t is in seconds. The work done during the first 4 seconds is

Work, Energy and Power

Question: A force acts on a 30 gm particle in such a way that the position of the particle as a function of time is given by $x = 3t - 4{t^2} + {t^3}$, where x is in metres and t is in seconds. The work done during the first 4 seconds is


1) 5.28 J
2) 450 mJ
3) 490 mJ
4) 530 mJ
Solution: Explanation: No Explanation
WEP Work Done by Constant Force

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