Laws of Motion

Question: A car is moving along a straight horizontal road with a speed ${v_0}$. If the coefficient of friction between the tyres and the road is $\mu $, the shortest distance in which the car can be stopped is

1) $\frac{{v_0^2}}{{2\mu g}}$

2) $\frac{{{v_0}}}{{\mu g}}$

3) ${\left( {\frac{{{v_0}}}{{\mu g}}} \right)^2}$

4) $\frac{{{v_0}}}{\mu }$

Solution:

Explanation: No Explanation

Friction Kinetic Friction

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