Laws of Motion

Question: The time period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with an acceleration g/3, the time period is

1) $T\sqrt 3 $

2) $T\sqrt 3 /2$

3) $T/\sqrt 3 $

4) $T/3$

Solution:

Explanation: No Explanation

Second Law of Motion NLM

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