Laws of Motion

Question: A boy having a mass equal to 40 kilograms is standing in an elevator. The force felt by the feet of the boy will be greatest when the elevator $(g = 9.8\,metres/{\sec ^2})$

1) Stands still

2) Moves downward at a constant velocity of 4 metres/sec

3) Accelerates downward with an acceleration equal to $4\,metres/{\sec ^2}$

4) Accelerates upward with an acceleration equal to $4\,metres/{\sec ^2}$

Solution:

Explanation: No Explanation

Second Law of Motion NLM

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