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Question: $_{90}^{232}Th$ an isotope of thorium decays in ten stages emitting six $\alpha$ -particles and four $\beta$ -particles in all. The end product of the decay is

1) $_{82}^{206}Pb$

2) $_{82}^{209}Pb$

3) $_{82}^{208}Pb$

4) $_{83}^{209}Br$

Solution:

Explanation: No Explanation

Radioactivity Modern Physics

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