Nuclei

Question: In the given nuclear reaction, $^{238}_{92} U \xrightarrow{\alpha}^{A}_{B} Th \xrightarrow{\beta}^C_DPa \xrightarrow{E}^{234}_{92} U$ A, B, C, D, E represents



1) A = 234, B = 90, C = 234, D = 91, E = $\gamma$
2) A = 234, B = 90, C = 238, D = 94, E = $\gamma$
3) A = 238, B = 93, C = 234, D = 91, E = $\gamma$
4) A = 234, B = 90, C = 234, D = 93, E = $\gamma$
Solution: Explanation: No Explanation
Radioactivity Modern Physics

Rate this question:

Average rating: (0 votes)

Previous Question Next Question