Categories > Nuclei > Nucleus > In the reaction $_1^2H + _1^3H \to _2^4He + _0^1n$. If the tending energies of $_1^2H,{\rm{ }}_1^3H{\rm{ and }}_2^4He$ are respectively $a,{\rm{ b and }}c$ (in MeV), then the energy (in MeV) released in this reaction is

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Question: In the reaction $_1^2H + _1^3H \to _2^4He + _0^1n$. If the tending energies of $_1^2H,{\rm{ }}_1^3H{\rm{ and }}_2^4He$ are respectively $a,{\rm{ b and }}c$ (in MeV), then the energy (in MeV) released in this reaction is


1) $c + a - b$
2) $c - a - b$
3) $a + b + c$
4) $a + b - c$
Solution: Explanation: No Explanation
Nucleus Nuclear Reaction Modern Physics

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