Categories > Nuclei > Nucleus > If 200 MeV energy is released in the fission of a single ${U^{235}}$nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given $1\;eV = 1.6 \times {10^{ - 19}}J$)

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Question: If 200 MeV energy is released in the fission of a single ${U^{235}}$nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given $1\;eV = 1.6 \times {10^{ - 19}}J$)


1) $3.125 \times {10^{13}}$
2) $3.125 \times {10^{14}}$
3) $3.125 \times {10^{15}}$
4) $3.125 \times {10^{16}}$
Solution: Explanation: No Explanation
Nucleus Nuclear Reaction Modern Physics

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