Categories > Nuclei > Nucleus > The binding energy of deuteron $_1^2H$is 1.112 MeV per nucleon and an $\alpha - $particle $_2^4He$has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction$_1^2H + _1^2H \to _2^4He + Q$, the energy Q released is

Nuclei

Question: The binding energy of deuteron $_1^2H$is 1.112 MeV per nucleon and an $\alpha - $particle $_2^4He$has a binding energy of 7.047 MeV per nucleon. Then in the fusion reaction$_1^2H + _1^2H \to _2^4He + Q$, the energy Q released is


1) 1 MeV
2) 11.9 MeV
3) 23.8 MeV
4) 931 MeV
Solution: Explanation: No Explanation
Nucleus Nuclear Reaction Modern Physics

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