Dual Nature of Radiation and Matter

Question: If we express the energy of a photon in KeV and the wavelength in angstroms, then energy of a photon can be calculated from the relation

1) $E = 12.4\,h\nu $

2) $E = 12.4\,h/\lambda $

3) $E = 12.4\,/\lambda $

4) $E = h\nu $

Solution:

Explanation: No Explanation

Photon and Photoelectric Effect

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