Dual Nature of Radiation and Matter

Question: The de-Broglie wavelength $\lambda $associated with an electron having kinetic energy E is given by the expression



1) $\frac{h}{{\sqrt {2mE} }}$
2) $\frac{{2h}}{{mE}}$
3) $2mhE$
4) $\frac{{2\sqrt {2mE} }}{h}$
Solution: Explanation: No Explanation
Matter Waves

Rate this question:

Average rating: (0 votes)

Previous Question Next Question