Categories > Dual Nature of Radiation and Matter > Cathode Rays and Positive Rays > In a Thomson set-up for the determination of e/m, electrons accelerated by 2.5 $kV$ enter the region of crossed electric and magnetic fields of strengths $3.6 \times {10^4}V{m^{ - 1}}$ and $1.2 \times {10^{ - 3}}T$ respectively and go through undeflected. The measured value of $e/m$ of the electron is equal to

Dual Nature of Radiation and Matter

Question: In a Thomson set-up for the determination of e/m, electrons accelerated by 2.5 $kV$ enter the region of crossed electric and magnetic fields of strengths $3.6 \times {10^4}V{m^{ - 1}}$ and $1.2 \times {10^{ - 3}}T$ respectively and go through undeflected. The measured value of $e/m$ of the electron is equal to


1) $1.0 \times {10^{11}}C{\rm{ - }}k{g^{ - 1}}$
2) $1.76 \times {10^{11}}C{\rm{ - }}k{g^{ - 1}}$
3) $1.80 \times {10^{11}}C{\rm{ - }}k{g^{ - 1}}$
4) $1.85 \times {10^{11}}C{\rm{ - }}k{g^{ - 1}}$
Solution: Explanation: No Explanation
Cathode Rays and Positive Rays

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