wave-optics

Question: A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $\varphi $. If $\mu $ represents the refractive index of glass with respect to air, then the angle between reflected and refracted rays is

1) $90 + \varphi $

2) ${\sin ^{ - 1}}(\mu \cos \varphi )$

3) 90o

4) ${90^o} - {\sin ^{ - 1}}(\sin \varphi /\mu )$

Solution:

Explanation: No Explanation

Polarisation of Light

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