Motion in A Straight Line

Question: A body is released from the top of a tower of height \[h\]. It takes \[v = \frac{1}{2}b{t^2} + {v_0}\] sec to reach the ground. Where will be the ball after time \[t/2\] sec



1) At \[h/2\]from the ground
2) At \[h/4\] from the ground
3) Depends upon mass and volume of the body
4) At \[3h/4\] from the ground
Solution: Explanation: Explanation
Motion under Gravity

Rate this question:

Average rating: (0 votes)

Previous Question Next Question