Electrostatics

Question: Two charges \[{q_1}\]and \[{q_2}\]are placed in vacuum at a distance \[d\] and the force acting between them is \[F\]. If a medium of dielectric constant 4 is introduced around them, the force now will be



1) \[4F\]
2) \[2F\]
3) \[\frac{F}{2}\]
4) \[\frac{F}{4}\]
Solution: Explanation: 4e

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