The velocity of water waves $$v$$ may depend upon their wavelength $$\lambda $$, the density of water $$\rho $$ and the acceleration due to gravity $$g$$. The method of dimensions gives the relation between these quantities as

Question

Accepted Answer

$${v^2} \propto g\lambda $$

Answer

$${v^2}rg$$

Answer

$${v^2} \propto g\lambda \rho $$

Answer

$${v^2} \propto {g^{ - 1}}{\lambda ^{ - 3}}$$

Units and Measurements

Question: The velocity of water waves \[v\] may depend upon their wavelength \[\lambda \], the density of water \[\rho \] and the acceleration due to gravity \[g\]. The method of dimensions gives the relation between these quantities as

Units and Measurements

Question: The velocity of water waves \[v\] may depend upon their wavelength \[\lambda \], the density of water \[\rho \] and the acceleration due to gravity \[g\]. The method of dimensions gives the relation between these quantities as

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