rotational-motion

Question: A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass K. If radius of the ball be R, then the fraction of total energy associated with its rotational energy will be

1) $\frac{{{K}^{2}}}{{{R}^{2}}}$

2) $\frac{{{K}^{2}}}{{{K}^{2}}+{{R}^{2}}}$

3) $\frac{{{R}^{2}}}{{{K}^{2}}+{{R}^{2}}}$

4) $\frac{{{K}^{2}}+{{R}^{2}}}{{{R}^{2}}}$

Solution:

Explanation: No Explanation

kinetic energy work and power

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