rotational-motion

Question: A uniform disc of mass $M$ and radius $R$ is rotating about a horizontal axis passing through its centre with angular velocity $\omega $. A piece of mass $m$ breaks from the disc and flies off vertically upwards. The angular speed of the disc will be

1) $\frac{(M-2m)\omega }{(M-m)}$

2) $\frac{(M+2m)\omega }{(M+m)}$

3) $\frac{(M-2m)\omega }{(M+m)}$

4) $\frac{(M+2m)\omega }{(M-m)}$

Solution:

Explanation: No Explanation

angular momentum

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