rotational-motion

Question: A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness t/4. The relation between the moments of inertia ${{I}_{A}}$ and ${{I}_{B}}$ is

1) ${{I}_{A}}>{{I}_{B}}$

2) $\frac{1}{R}\sqrt{mgh/(M+m)}$

3) $\frac{1}{R}\sqrt{8mgh/(M+2m)}$

4) Depends on the actual values of t and r

Solution:

Explanation: No Explanation

moment of inertia

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