rotational-motion

Question: A thin wire of length $L$ and uniform linear mass density $\rho$ is bent into a circular loop with centre at O as shown. The moment of inertia of the loop about the axis $XX'$ is

1) $\frac{\rho {{L}^{3}}}{8{{\pi }^{2}}}$

2) $\frac{\rho {{L}^{3}}}{16{{\pi }^{2}}}$

3) $\frac{5\rho {{L}^{3}}}{16{{\pi }^{2}}}$

4) $\frac{3\rho {{L}^{3}}}{8{{\pi }^{2}}}$

Solution:

Explanation: No Explanation

moment of inertia

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