rotational-motion

Question: The adjoining figure shows a disc of mass M and radius R lying in the X-Y plane with its centre on $X-$axis at a distance $a$ from the origin. Then the moment of inertia of the disc about the X-axis is

1) $M\,\left( \frac{{{R}^{2}}}{2} \right)$

2) $M\,\left( \frac{{{R}^{2}}}{4} \right)$

3) $M\,\left( \frac{{{R}^{2}}}{4}+{{a}^{2}} \right)$

4) $M\,\left( \frac{{{R}^{2}}}{2}+{{a}^{2}} \right)$

Solution:

Explanation: No Explanation

moment of inertia

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