rotational-motion

Question: Four particle of masses m, 2m, 3m and 4m are arranged at the corners of a parallelogram with each side equal to a and one of the angle between two adjacent sides is $60^o$. The parallelogram lies in the x-y plane with mass m at the origin and 4m on the x-axis. The centre of mass of the arrangement will be located at



1) $\left( \frac{\sqrt{3}}{2}a,\,\,0.95a \right)$
2) $\left( \,0.95a,\,\,\frac{\sqrt{3}}{4}a\, \right)$
3) $\frac{3a}{4}, \frac{a}{2}$
4) $\left( \frac{a}{2},\,\,\frac{3a}{4} \right)$
Solution: Explanation: No Explanation
centre of mass

Rate this question:

Average rating: (0 votes)

Previous Question Next Question