statics

Question: Three like parallel forces P,Q, R act at the corners A,B,C of a $\Delta ABC$. If their resultant passes through the incentre of $\Delta ABC$, then



1) $\frac{P}{a}+\frac{Q}{b}+\frac{R}{c}=0$
2) $Pa+Qb+Rc=0$
3) $\frac{P}{a}=\frac{Q}{b}=\frac{R}{c}$
4) $Pa=Qb=Rc$
Solution: Explanation: No Explanation
Parallel forces Moment and Couples

Rate this question:

Average rating: (0 votes)

Previous Question Next Question