statics

Question: P, Q, R are the points on the sides BC, CA, AB of the triangle ABC such that $BP:PC=CQ:QA=AR:RB=m:n$. If $\Delta $denotes the area of the $\Delta ABC$, then the forces $\overrightarrow{AP},\overrightarrow{BQ},\overrightarrow{CR}$ reduce to a couple whose moment is



1) $2\frac{m+n}{m-n}\Delta $
2) $2\frac{n-m}{n+m}\Delta $
3) $2({{m}^{2}}-{{n}^{2}})\Delta $
4) $2({{m}^{2}}+{{n}^{2}})\Delta $
Solution: Explanation: No Explanation
Parallel forces Moment and Couples

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