Categories > statics > Composition and resolution of forces and condition of equilibrium of forces > The resultant of two forces P and Q acting at an angle $\theta $is equal to $(2m+1)$$\sqrt{{{P}^{2}}+{{Q}^{2}}}$; when they act at an angle ${{90}^{o}}-\theta $, the resultant is $(2m-1)$$\sqrt{{{P}^{2}}+{{Q}^{2}}}$; then $\tan \theta $=

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Question: The resultant of two forces P and Q acting at an angle $\theta $is equal to $(2m+1)$$\sqrt{{{P}^{2}}+{{Q}^{2}}}$; when they act at an angle ${{90}^{o}}-\theta $, the resultant is $(2m-1)$$\sqrt{{{P}^{2}}+{{Q}^{2}}}$; then $\tan \theta $=


1) $\frac{1}{m}$
2) $\frac{m+1}{m-1}$
3) $\frac{m-1}{m+1}$
4) $\sqrt{1+{{m}^{2}}}$
Solution: Explanation: No Explanation
Composition and resolution of forces and condition of equilibrium of forces

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