Categories > diff-equation > Miscellaneous differential equations > The solution of the equation $\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}$ is

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Question: The solution of the equation $\frac{{{d}^{2}}y}{d{{x}^{2}}}={{e}^{-2x}}$ is


1) $\frac{1}{4}{{e}^{-2x}}$
2) $\frac{1}{4}{{e}^{-2x}}+cx+d$
3) $\frac{1}{4}{{e}^{-2x}}+c{{x}^{2}}+d$
4) $\frac{1}{4}{{e}^{-2x}}+c+d$
Solution: Explanation: No Explanation
Miscellaneous differential equations

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