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Question: Solution of the differential equation $\frac{dy}{dx}+y{{\sec }^{2}}x=\tan x{{\sec }^{2}}x$ is


1) $y=\tan x-1+c{{e}^{-\tan x}}$
2) ${{y}^{2}}=\tan x-1+c{{e}^{\tan x}}$
3) $y{{e}^{\tan x}}=\tan x-1+c$
4) $y{{e}^{-\tan x}}=\tan x-1+c$
Solution: Explanation: No Explanation
Linear differential equations

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