diff-equation

Question: The solution of the differential equation $\frac{dy}{dx}+\frac{3{{x}^{2}}}{1+{{x}^{3}}}y=\frac{{{\sin }^{2}}x}{1+{{x}^{3}}}$ is

1) $y(1+{{x}^{3}})=x+\frac{1}{2}\sin 2x+c$

2) $y(1+{{x}^{3}})=cx+\frac{1}{2}\sin 2x$

3) $y(1+{{x}^{3}})=cx-\frac{1}{2}\sin 2x$

4) $y(1+{{x}^{3}})=\frac{x}{2}-\frac{1}{4}\sin 2x+c$

Solution:

Explanation: No Explanation

Linear differential equations

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