diff-equation

Question: The general solution of the differential equation $ydx\,+(1+{{x}^{2}}){{\tan }^{-1}}xdy=0,$ is

1) $y{{\tan }^{-1}}x=c$

2) $x{{\tan }^{-1}}y=c$

3) $y+{{\tan }^{-1}}x=c$

4) $x+{{\tan }^{-1}}y=c$

Solution:

Explanation: No Explanation

Variable separable type differential equations

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